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| author | Andrea Gelmini <andrea.gelmini@gelma.net> | 2018-11-24 23:36:55 +0100 |
|---|---|---|
| committer | Julien Nabet <serval2412@yahoo.fr> | 2018-11-25 00:15:25 +0100 |
| commit | 2cc09c4650c2fc6acc0157cd26acad248f32c5ac (patch) | |
| tree | 56787a315e6c78d9ea4e8779342dd9818ebbe50e /basegfx | |
| parent | 878c36f829fd88cda95ca218a2cf03003f50e53d (diff) | |
Fix typo
Change-Id: I8e90b4592d041e63bd2efa914446db96dd293ac9
Reviewed-on: https://gerrit.libreoffice.org/63964
Reviewed-by: Julien Nabet <serval2412@yahoo.fr>
Tested-by: Julien Nabet <serval2412@yahoo.fr>
Diffstat (limited to 'basegfx')
| -rw-r--r-- | basegfx/source/polygon/b2dtrapezoid.cxx | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/basegfx/source/polygon/b2dtrapezoid.cxx b/basegfx/source/polygon/b2dtrapezoid.cxx index 9bff42a0d0a6..9ddeed3309b9 100644 --- a/basegfx/source/polygon/b2dtrapezoid.cxx +++ b/basegfx/source/polygon/b2dtrapezoid.cxx @@ -588,7 +588,7 @@ namespace basegfx { // This is the central subdivider. The strategy is to use the first two entries // from the traversing edges as a potential trapezoid and do the needed corrections - // and adaptions on the way. + // and adaptations on the way. // There always must be two edges with the same YStart value: When adding the polygons // in the constructor, there is always a topmost point from which two edges start; when @@ -661,7 +661,7 @@ namespace basegfx B2DPoint aLeftEnd(aLeft.getEnd()); B2DPoint aRightEnd(aRight.getEnd()); - // check if end points are on the same line. If yes, no adaption + // check if end points are on the same line. If yes, no adaptation // needs to be prepared. Also remember which one actually is longer. const bool bEndOnSameLine(fTools::equal(aLeftEnd.getY(), aRightEnd.getY())); bool bLeftIsLonger(false); |