From 2cc09c4650c2fc6acc0157cd26acad248f32c5ac Mon Sep 17 00:00:00 2001
From: Andrea Gelmini <andrea.gelmini@gelma.net>
Date: Sat, 24 Nov 2018 23:36:55 +0100
Subject: Fix typo
Change-Id: I8e90b4592d041e63bd2efa914446db96dd293ac9
Reviewed-on: https://gerrit.libreoffice.org/63964
Reviewed-by: Julien Nabet <serval2412@yahoo.fr>
Tested-by: Julien Nabet <serval2412@yahoo.fr>
---
basegfx/source/polygon/b2dtrapezoid.cxx | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
(limited to 'basegfx')
diff --git a/basegfx/source/polygon/b2dtrapezoid.cxx b/basegfx/source/polygon/b2dtrapezoid.cxx
index 9bff42a0d0a6..9ddeed3309b9 100644
--- a/basegfx/source/polygon/b2dtrapezoid.cxx
+++ b/basegfx/source/polygon/b2dtrapezoid.cxx
@@ -588,7 +588,7 @@ namespace basegfx
{
// This is the central subdivider. The strategy is to use the first two entries
// from the traversing edges as a potential trapezoid and do the needed corrections
- // and adaptions on the way.
+ // and adaptations on the way.
// There always must be two edges with the same YStart value: When adding the polygons
// in the constructor, there is always a topmost point from which two edges start; when
@@ -661,7 +661,7 @@ namespace basegfx
B2DPoint aLeftEnd(aLeft.getEnd());
B2DPoint aRightEnd(aRight.getEnd());
- // check if end points are on the same line. If yes, no adaption
+ // check if end points are on the same line. If yes, no adaptation
// needs to be prepared. Also remember which one actually is longer.
const bool bEndOnSameLine(fTools::equal(aLeftEnd.getY(), aRightEnd.getY()));
bool bLeftIsLonger(false);
--
cgit