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path: root/sal/qa/rtl/strings/test_strings_valuex.cxx
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2019-09-24support O(U)String::number() for fast string concatenationLuboš Luňák
When I did the fast string concatenation, I didn't add any support for number(), which simply returned a O(U)String, and so it did the extra allocation/deallocation, although that could be avoided. In order to support this, number() now returns a special temporary return type, similarly to O(U)StringConcat, which allows delaying the concatenation the same way. Also similarly, the change of the return type in some cases requires explicit cast to the actual string type. Usage of OString::getStr() is so extensive in the codebase that I actually added it to the helper class, after that it's only relatively few cases. Change-Id: Iba6e158010e1e458089698c426803052b6f46031 Reviewed-on: https://gerrit.libreoffice.org/78873 Tested-by: Jenkins Reviewed-by: Luboš Luňák <l.lunak@collabora.com>
2018-10-24remove more rtl::OUString and OString prefixesNoel Grandin
which seem to have snuck back in since the great rounds of removals. Change-Id: I85f7f5f4801c0b48dae8b50f51f83595b286d6a1 Reviewed-on: https://gerrit.libreoffice.org/62229 Tested-by: Jenkins Reviewed-by: Noel Grandin <noel.grandin@collabora.co.uk>
2018-09-17New loplugin:externalStephan Bergmann
...warning about (for now only) functions and variables with external linkage that likely don't need it. The problems with moving entities into unnamed namespacs and breaking ADL (as alluded to in comments in compilerplugins/clang/external.cxx) are illustrated by the fact that while struct S1 { int f() { return 0; } }; int f(S1 s) { return s.f(); } namespace N { struct S2: S1 { int f() { return 1; } }; int f(S2 s) { return s.f(); } } int main() { return f(N::S2()); } returns 1, both moving just the struct S2 into an nunnamed namespace, struct S1 { int f() { return 0; } }; int f(S1 s) { return s.f(); } namespace N { namespace { struct S2: S1 { int f() { return 1; } }; } int f(S2 s) { return s.f(); } } int main() { return f(N::S2()); } as well as moving just the function f overload into an unnamed namespace, struct S1 { int f() { return 0; } }; int f(S1 s) { return s.f(); } namespace N { struct S2: S1 { int f() { return 1; } }; namespace { int f(S2 s) { return s.f(); } } } int main() { return f(N::S2()); } would each change the program to return 0 instead. Change-Id: I4d09f7ac5e8f9bcd6e6bde4712608444b642265c Reviewed-on: https://gerrit.libreoffice.org/60539 Tested-by: Jenkins Reviewed-by: Stephan Bergmann <sbergman@redhat.com>